Prof. Alejandro Ucan-Puc
The derivative and anti-derivative are transformations of functions, and can be thought of as linear transformations.
Remember that through anti-derivatives we can define functions.
Some problems (stated in some domain) are difficult to solve in their original presentation, but transformed can be simpler. The integral transform maps an equation in its original "domain" into another "domain" in such a way that the manipulation of the equation is simpler than originally and the solution can be reconverted to the original domain.
Definition: the Laplace transform of a function $f(t)$ with $t\geq 0$ is the function $F(s)$ defined by $$F(s)=\int_0^\infty f(t)e^{-st}dt=\lim_{b\to\infty}\int_0^b f(t)e^{-st}$$ where $s$ is a parameter.
The usual notation for the Laplace transform is $\mathcal{L}\{f(t)\}=F(s).$
Compute the Laplace transforms of $f(t)=1$ and $f(t)=t.$
Compute the Laplace transform of: $f(t)=-3t^2+2t+1,$ $f(t)=\cos(3t)$ and $f(t)=e^{2t}.$
The Laplace transform calculation is something that you do only once, because there are some formulaes that you can use directly.
Theorem: It follows that:
Linearity: Let $f$ and $g$ be two functions defined on $[0,\infty)$ such that their Laplace transforms exist, then $$\mathcal{L}\{c_1 f+c_2 g\}=c_1\mathcal{L}\{f\}+c_2 \mathcal{L}\{g\}.$$
Using Linearity in the Laplace transform, transform the following functions:
Using the integral definition, compute the Laplace transform of the following functions:
Integral transform concept, formal definition, Laplace transforms of elementary functions, algebraic linearity, and piecewise forcing functions.
Next Session: Applied Laplace Transform & IVPs